Archive for the ‘Articles in English’ Category

Machine Learning for dummies – Neural Networks

Tuesday, February 16th, 2016

Even though Neural Networks are the most cool thing in machine learning, they conceptually are just multiple linear regressions chained one after the other. So I will not draw any fancy pictures of neurons, I will just write boring matrix multiplications. Both representations are equivalent.

Last time, we have learned that logistic regression classification is just matter taking sample x, multiplying it by matrix W and adding some constant bias term b. In our letter recognition example x is 784-dimensional vector, W is 10x784 dimensional matrix and b is 10-dimensional vector. Once our model learns weights W and b, we just calculate W x + b and pick the row with the maximal value. Index of the row is our class prediction.

The downside of logistic regression is that it can only classify classes that are separable by linear plane. We can fix that by adding multiple linear regressions one after each other.

Let's say that we take the input, multiply it by a matrix, add bias and then take the output. x_2 := W_1 x + b_1 We can again multiply it by another matrix and add another bias y:= W_2 x_2 + b_2 We then can take the result of this second operation and use it as our prediction.

We will call this Neural Network with one hidden layer. The hidden layer is the vector x_2. It is hidden because nobody sees it, it's just something internal to the model. It's up to us to decide what the size of x_2 will be. The size is usually called number of neurons in the hidden layer. We can even add more hidden layers, each with different size. Unfortunately no one will tell you how many layers and how big they should be, you have to play with the parameters and see how the network performs.

To make things even more complicated, you can also use activation function. Activation function can take the result of each layer and make it more non-linear. So we will get x_2:= g(W_1 x + b_1) where g is the activation function. Popular choices are relu, tanh and for the last layer softmax.

Luckily for us, it's quite simple to play with neural networks in Python. There are several libraries, I have picked Keras, since it's quite powerful and easy to use.

from keras.models import Sequential
from keras.layers.core import Dense, Activation
from keras.optimizers import SGD

model = Sequential()
# Hidden layer with 1024 neurons
model.add(Dense(output_dim=1024, input_dim=image_size * image_size, init="glorot_uniform"))
# ReLU activation
model.add(Activation("relu"))
# We have 10 letters
model.add(Dense(output_dim=10, init="glorot_uniform"))
# Softmax makes sense for the activation of the output layer
model.add(Activation("softmax"))

# Let the magic happen
model.compile(loss='categorical_crossentropy', optimizer=SGD())

model.fit(train_dataset, train_labels, batch_size=128, nb_epoch=50)

In this example we will create a neural network with one hidden layer of 1024 neurons with activation function ReLU. In other words (ignoring biases), we will take the pixels of the letter, multiply them by a matrix which will result in 1024 numbers. We will then set all the negative numbers to 0 (ReLU) and then multiply the result by another matrix to get 10 numbers. We then find the highest of those numbers. Let's say that highest result is in second row then the resulting letter is B.

We of course need to train the network. It's more complex, luckily we do not need to know much about it. So let's just use Stochastic Gradient Descent with batch size 128. nb_epoch says that we should walk through all training examples 50-times. Please remember that training is just finding of the minimum of some loss function.

I am using Keras with Tensorflow so when I call model.compile it actually generates some optimized distributed parallel C++ code that can even run on GPU. The code will train the network for us. This is important, large networks with lots of hidden layers and lots of parameters can take ages and lot of calculations to learn. Keras and Tensorflow hides the complexity so I do not have to worry about it.

And what about the results? We get 96% accuracy on test set! Another 3% increase from SVM. Since the best result on notMNIS is allegedly 97.1% I think it's not bad at all. Can you calculate how many parameters we do have? In the first layer we have matrix of 1024x784 parameters + 1024 bias terms. In the output layer we have 10x1024 + 10 parameters. In total it's around 800,000 parameters. Training takes around 20 minutes on my laptop.

Machine Learning for dummies – Logistic Regression internals

Tuesday, February 9th, 2016

Before we can start with neural networks, we should talk a bit more about Logistic Regression – without understanding Logistic Regression, we can not understand neural networks. Moreover, I have learned how to use math in WordPress so I need to try it.

As we already know, Logistic Regression tries to find linear hyperplane that separates two classes. Hyperplane is a thing that has one dimension less than the thing it is in. If we have 1-dimensional space (line), hyperplane is a one-dimensional point. If we have 3D space a hyperplane is a 2D plane. And if we have 784-dimensional space a hyperplane is a 783-dimensional space.

Let's start with 1D example. We have a line and we want to separate it to two segments. We need to find or define one point that separates those two segments. We can define it like this x_1 - 5. If x_1 > 5, we get positive value from the equation and the point is in one segment (class). If x_1<5, the result is negative and the sample is in the other class. In 3D it's similar, we just need more parameters: 2x_1 + 3x_2 + 4x_3 + 5. When we plug-in our sample, we can again decide if the equation returns positive or negative value. Easy

Generic definition of a hyperplane in n-dimensional space looks like this w_1 x_1 +  w_2 x_2 + ... + w_n x_n + b. If we use vectors w and x, we can define hyperplane using vector multiplication w^T x + b. But how to get those parameters (a.k.a weights) w? We need to learn them form training samples.

First of all, we will define labels y as follows. y=1 if it's a positive example and y=0 if it's a negative one. We will only deal with two classes and cover multiple classes later. In our letter classification we will set y=1 if the training example is an 'A'. Now we need to be able to somehow compare output from w^T x + b and y. The trouble is that w^T x + b is an unbounded real number and we need to somehow make it comparable to y which is zero or one. That's where we will use logistic function (hence the name Logistic Regression). The details are described here, for us dummies it suffices to say that Logistic Function maps real numbers to interval 0 to 1 in a way that is good. Like really good. It's so good I will give it a name g. So now we have g(w^T x + b) which returns numbers between zero and one.

Thanks to logistic function we can now compare results of our model with the training labels. Imagine that we have already obtained parameters w, we can measure how well the parameters classify our training set. We just have to somehow calculate the distance from prediction. In ML the distance is called cost function. With linear regression people use cross-entropy and again, I will not go into details here. We just need to know that it returns 0 if our model classifies the sample correctly and some really really high number if it classifies it incorrectly.

If we put it together, we can calculate Cost(g(w^T x + b), y) for each pair x and y. If model makes correct prediction, the cost is zero, if it mis-predicts, the cost is high. We can even calculate a sum over all m training examples: J(w) = \sum\limits_{i=1}^m(Cost(g(w^T x^(i) + b^(i)), y^(i))). If the sum is large, our model is bad and if the sum is 0 our model is the best. Function J(w) is function of parameters w, we have made our training samples and labels part of the function definition. Now the only thing we need is to find such w so the function J(w) is as small as possible.

And that's how the model learns. We needed all those strange functions just to make this final function nice, having only one global minimum and other nice properties. While it's possible to find the minimum analytically, for practical reasons it's usually found by using something called gradient descent. I will not go to the details, it basically just generates random parameters w, calculates J(w) and then it does small change to parameters so the next J(w) is a bit smaller. It then iterates until it reaches the minimum. That's all we need to know for now.
Please note that we need all those strange functions mainly for learning. When classifying, I can still calculate w^T x + b and if it's positive, it's a letter 'A' and if it's negative it's some other letter. The advantage of applying the logistic function is that I can interpret the result as a probability.

What about multiple classes? We can use one-vs-all classifier. We can train a classifier that is able to separate A's from the rest of the letters. Then B's from the rest and so on. For our 10 letters we can apply the algorithm described above ten-times. Or we can use few tricks and learn all the letters in one pass.

The first trick is to change our labeling method. Before, we set y=1 if the letter in training set was an 'A'. With multiple letters, we will use y=[1,0,0,...]^T for 'A', y=[0,1,0,...]^T for 'B', y=[0,0,1,...]^T for 'C' etc. We also need to train different set of parameters (weights) for each letter. We can add all the weights into one matrix W and calculate the result using matrix multiplication W x + b (b is 10-dimensional vector now as well). If we put weights for each letter to W as a row, our matrix will have 10 rows (one for each letter) and 784 columns (one for each pixel). Our sample x has 784 rows. If we multiply the two, we will get 10 numbers. We then element-wise add 10-numbers from b and pick the largest one. That's our prediction. For learning, we will use softmax function instead of logistic function, but the rest remains the same. At the end of the learning we will get 10x784 + 10 numbers that define 10 hyperplanes separating letters in 784-dimensional space.

If case you are wondering why you need to know all of this, the reason is simple. Neural networks are built on top of ideas from logistic regression. In other words, logistic regression is one-layer neural network so in order to make real NN, we just need to add more layers. This is how our logistic regression looks like if depicted as a single neuron

Logistic Regression

Machine learning for dummies – Support Vector Machines

Sunday, February 7th, 2016

Support Vector Machines, it sounds scary. Might be a name of some horror movie. Revenge of Support Vector Machines. But do not worry, for us dummies it's not so complicated. I promise I will not use any intimidating words such as Lagrangian or Mercer's Theorem. To make it even simpler, I will just talk about classification between two classes, as if we were trying to decide if a letter is an 'A' or not (please read previous post if you do not know what I am talking about).

SVMs are really similar to Logistic Regression, they try to find linear (hyper)plane that would separate our classes, one class on one side of the plane, the other on the other side. There are two important differences from Logistic Regression. The first one is that SVMs try to find plane that is as far as possible from both classes. But that's not so interesting. When trying to classify letters, our problem is that most likely you can not find any such plane in our 784 dimensional space (28x28 pixels) that would separate A's from other letters.

Imagine that we got to situation on the image below. For simplicity only in 2 dimension, as if our letters had only two pixels. (images taken from Everything You Wanted to Know about the Kernel Trick)

Kernel Trick

Imagine that our A's are in the middle surrounded by their enemies, other letters. I just can not draw a straight line to separate them.

But I can escape to another dimension by creating a third feature like $latex x_1^2 + x_2^2$ (image on the right). Now I can separate the two classes. Look ma, I can draw a circle using a linear function!

Kernel Trick

While I can manually find a new feature that would separate the classes, I am to lazy to do that. It's called Machine Learning, I want the machine to do it for me. SVMs can hep me with that. I can ask them to use a “kernel” which will make my model non-linear. Here is how it works, hopefully sufficiently dummified.

Imagine I have 20,000 training samples. The first thing the model does is that it remembers them all. It just shamelessly stores all 20k samples. Now imagine I have a new sample coming to the model. The model calculates distances from my 20k training samples to my new sample which results in 20k new features. First feature is the distance to the first sample in my training set, second is the distance to the second sample etc. Suddenly I have twenty-thousand-dimensional space and it's much more likely that I will find a linear plane that would separate both classes. This method intuitively makes sense. Points representing A's are likely to be near other point's representing A's so if we somehow incorporate distance into the model, it should get better result. In more clever sounding words, if I project the plane form 20k dimensional space back to my original 784 dimensional space, I can get highly nonlinear boundary.

Now a bit less dummified version (dummified is a word, I swear). Not all 20k training samples are used, only the most interesting ones (they are called Support Vectors hence the name). So the space we are using has less than 20k dimensions. Moreover the distance is not necessary a distance, it's just some function that takes two points (vectors) as an input and returns a number (new feature). This function is called kernel and we pick it when configuring the classifier - Gaussian (rbf) is the most common. And while the method sounds complicated and slow, it uses some mathematical shortcuts so it's relatively fast. Unfortunately it does not scale well with number of training samples.

Let's see how the method looks in the code.

clf = svm.SVC(C=10, gamma=0.01, cache_size=2000) 

The rest of the code is the same as the last time, we've just changed the classifier. We see our favorite (hyper)parameter C. There is also a new parameter 'gamma' which configures the kernel. Smaller gamma makes our Support Vectors reach further and generalize more.

So what are the results? We got to 99.7% accuracy on the training set. It's not surprising, the model actually remembers some of the training samples. If we call 'clf.support_.shape' it will tell us that it remembers 8,670 samples out of 20,000. It means that our model has to learn 8,670 parameters for each classified class. Let's count how many numbers the model needs to remember. It stores 8,670 samples each of them having 28x28=784 values. We are trying to classify 10 letters so the model learns 10x8,670 parameters. (Actually 9x8,670, but let's not go there.) All in all, the model consists of almost 7,000,000 parameters (numbers) most of it in form of Support Vectors picked from training samples. The training takes less than 3 minutes on my laptop.

What are the results on the validation set, on the samples that the model has not seen? It is 87%. The nonlinearity of the model gave us five more percent when compared to Logistic Regression. It's great. The author of notMNIST set says that the set has ~6,5% label error rate so we need six more percent to get perfect. To confirm that I could not resist and run the classification on test set, which is much cleaner. I got 93% accuracy. Like 93% on this crazy images? Incredible. We still have further 6-7% to go and I am afraid we will have to resort to neural networks to get better results.

Sources:
Coursera Machine Learning Course
Everything You Wanted to Know about the Kernel Trick
scikit learn documentation on RBF SVM parameters
scikit learn documentation on SVC